Quadratic Equations:Part2
Finding the roots of a quadratic equation using the factorization method
We take a quadratic equation:
x^2 + 5x + 6 = 0
First, we check whether there is any coefficient of x2.
This means we see if any number other than 1 is multiplied with .
If the coefficient of is 1, then we factor the last number (6) in such a way that the sum of the factors is 5 (or −5, depending on the sign of the middle term).
Finding the Roots of a Quadratic Equation by Factorization Method
We take a quadratic equation:
x^2 + 5x + 6 = 0
First, we check the coefficient of x^2.
If the coefficient of x^2 is 1, we factor the last term in such a way that the sum of the factors is equal to the coefficient of x.
The factors of 6 are 2 and 3, and:
2 + 3 = 5
So, the equation becomes:
x^2 + 3x + 2x + 6 = 0
Now taking common factors:
x(x + 3) + 2(x + 3) = 0
(x + 3)(x + 2) = 0
Equating each factor to zero:
x + 3 = 0
x = -3
x + 2 = 0
x = -2
Hence, the roots of the equation are:
x = -3 and x = -2
When the coefficient of is not 1
Example:
Consider the quadratic equation:
2x^2 + 7x + 3 = 0
Step 1:
Multiply the coefficient of x² with the constant term.
2 × 3 = 6
Step 2:
Find two numbers whose product is 6 and sum is 7.
These numbers are 6 and 1.
Step 3:
Split the middle term using these numbers.
2x^2 + 6x + x + 3 = 0
Step 4:
Take common factors.
2x(x + 3) + 1(x + 3) = 0
Step 5:
Factorize.
(2x + 1)(x + 3) = 0
Step 6:
Equate each factor to zero.
Equate each factor to zero.
2x + 1 = 0
x = -1/2
x + 3 = 0
x = -3
Hence, the roots of the equation are:
x = -1/2 and x = -3
Practice Set: Quadratic Equations (Factorization Method)
Solve the following quadratic equations:
1. x^2 + 7x + 10 = 0
2. x^2 + 9x + 20 = 0
3. x^2 + 11x + 24 = 0
4. 2x^2 + 5x + 3 = 0
5. 3x^2 + 11x + 6 = 0
6. 4x^2 + 12x + 9 = 0
7. 2x^2 − 7x + 3 = 0
Here are only the answers π
1. x = −5, −2
2. x = −5, −4
3. x = −3, −8
4. x = −1, −3/2
5. x = −2, −1
6. x = −3/2, −3/2
7. x = 3, 1/2
8. x = 2, 6
By: SYED DANISH SHAHEZAD
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